Mathematics Mock Test
Mathematics Mock Test
Test your knowledge with these math questions
Test Instructions
  • This test contains 5 multiple-choice questions
  • Each question is worth 1 mark
  • You have 15 minutes to complete the test
  • There is negative marking (0.25 points per wrong answer)
  • You can navigate between questions using Next and Previous buttons
  • After submission, you can review explanations for each question
Candidate:
Time Left: 15:00
Question 1 of 5
What is the derivative of \(f(x) = 3x^4 – 2x^3 + 5x – 7\)?
Question 2 of 5
Given the matrices \(A = \begin{bmatrix} 2 & 3 \\ 1 & -1 \end{bmatrix}\) and \(B = \begin{bmatrix} 4 & -2 \\ 0 & 5 \end{bmatrix}\),
what is the product \(A \times B\)?
Question 3 of 5
Simplify the expression: \(\sin^2(x) + \cos^2(x)\)
Question 4 of 5
What is the solution to the equation \(2x^2 – 4x – 6 = 0\)?
Question 5 of 5
What is the value of \(\lim_{x \to 0} \frac{\sin(x)}{x}\)?

Test Results

Score: 0 out of 5
Question Explanations

Question 1: Derivative

Your answer: Not answered

Correct answer: a) \(12x^3 – 6x^2 + 5\)

Explanation: The derivative of a polynomial is found by applying the power rule to each term. For \(3x^4\), the derivative is \(12x^3\); for \(-2x^3\), it’s \(-6x^2\); for \(5x\), it’s \(5\); and the derivative of a constant \(-7\) is \(0\).

Question 2: Matrix Multiplication

Your answer: Not answered

Correct answer: a) \(\begin{bmatrix} 8 & 11 \\ 4 & -7 \end{bmatrix}\)

Explanation: Matrix multiplication is performed by taking the dot product of rows and columns. For the first row: \(2*4 + 3*0 = 8\), \(2*(-2) + 3*5 = -4 + 15 = 11\). For the second row: \(1*4 + (-1)*0 = 4\), \(1*(-2) + (-1)*5 = -2 – 5 = -7\).

Question 3: Trigonometric Identity

Your answer: Not answered

Correct answer: b) \(1\)

Explanation: This is the Pythagorean trigonometric identity. For any angle \(x\), \(\sin^2(x) + \cos^2(x) = 1\). This is one of the most fundamental identities in trigonometry.

Question 4: Quadratic Equation

Your answer: Not answered

Correct answer: a) \(x = -1, x = 3\)

Explanation: Solve using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}\). Here, \(a=2\), \(b=-4\), \(c=-6\). The discriminant is \(16 + 48 = 64\), so \(x = \frac{4 \pm 8}{4}\), which gives \(x = 3\) and \(x = -1\).

Question 5: Limit

Your answer: Not answered

Correct answer: b) \(1\)

Explanation: This is a standard limit in calculus. As \(x\) approaches 0, \(\frac{\sin(x)}{x}\) approaches 1. This can be proven using the squeeze theorem or L’Hôpital’s rule.